Electromagnetic waves radiating away from a transmitting tower

AI Thread Summary
A radio station radiates a sinusoidal wave with an average power of 50 kW, assuming equal radiation in all directions. The intensity is calculated by dividing the power by the surface area of a half-sphere at a distance of 100 km. The relationship between intensity and the electric field is expressed as I = cε0E², allowing for the calculation of Emax. To find Bmax, Emax is divided by the speed of light, c. The discussion concludes that to obtain the average intensity, the instantaneous intensity must be divided by 2, leading to the correct result.
DottZakapa
Messages
239
Reaction score
17
Homework Statement
A radio station on the surface of the earth radiates a sinusoidal wave with an average total power of 50 kw. Assuming that the transmitter radiates equally in all the directions above the ground, at a distance of 100 km from the antenna (ε0 = 8.85 10-12 C2N-1m-2)
Relevant Equations
electromagnetic waves
Homework Statement: A radio station on the surface of the Earth radiates a sinusoidal wave with an average total power of 50 kw. Assuming that the transmitter radiates equally in all the directions above the ground, at a distance of 100 km from the antenna (ε0 = 8.85 10-12 C2N-1m-2)
Homework Equations: electromagnetic waves

I divide the power by the half sphere
50000/(4πr2/2)
In such way i get the intensity per surface unity right?
which is also equal to
I=cε0E2
Now, from this equation i solve for E if i want to get Emax right ?
In case i need Bmax i divide Emax by c
Is there any error ? because can't get the right result
 
Last edited:
Physics news on Phys.org
DottZakapa said:
I divide the power by the half sphere
50000m/((4πr2)/2)
In such way i get the intensity per surface unity right?
That's the right approach (but I don't know what the "m" is for in your expression).
DottZakapa said:
which is also equal to
I=cε0E2
Where did you get that equation?
 
Doc Al said:
That's the right approach (but I don't know what the "m" is for in your expression).

Where did you get that equation?
that equation comes from:

Screen Shot 2019-08-25 at 20.26.43.png
total energy density

Screen Shot 2019-08-25 at 20.27.07.png
relation between E and B

Screen Shot 2019-08-25 at 20.27.15.png


Screen Shot 2019-08-25 at 20.28.10.png
energy flow per unit area per unit time

But i realized that this leads to instantaneous intensity, in order to get the average intensity , S must be divided by 2.
Doing so you get the average intensity,

Screen Shot 2019-08-25 at 20.39.21.png


which leads to the correct result.
Thanks 👍 very kind.
 
DottZakapa said:
But i realized that this leads to instantaneous intensity, in order to get the average intensity , S must be divided by 2.
Exactly. Good work!
 
  • Like
Likes DottZakapa
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top