Electromagnetism — finding the current

AI Thread Summary
A 35-loop square coil measuring 0.12 m per side is placed in a 0.050 T magnetic field, with a 0.20 kg mass suspended from it. The discussion focuses on calculating the current required for the coil to remain horizontal, using torque and force equations. The torque (τ) is derived from the weight of the mass, calculated as τ = Fl, where F is the force due to gravity and l is the distance from the axis. The participant successfully calculates the torque as 0.1176 Nm and expresses a clearer understanding of the relationship between torque and current. The conversation emphasizes the importance of unit consistency for accurate calculations.
physics604
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1. A 35 loop square coil 0.12 m on a side is positioned in a 0.050 T magnetic field. A 0.20 kg
mass is suspended from one side of the coil as shown in the diagram attached. How much current must pass through the coil in order for the coil to remain horizontal?

A. 2.3 A
B. 4.7 A
C. 9.3 A
D. 330 A

Homework Equations



τ=BAIN
F=IlB

The Attempt at a Solution



τ=BAIN
so I=τ/BAN

I know that BAN is 0.050 x 0.122 x 35 (the information is given). However, I'm having a little trouble finding τ (torque).

I know that I need to find the forces on the square coil. But since I don't know I (current), I won't be able to find the force with the equation.

Any help would be greatly appreciated.
 

Attachments

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The required force is given by the mass. Which torque do you get from the mass?
The coil has to compensate this with its own torque.
 
That's alright, I finally understand it now.

τ = Fl = 0.20x9.8x0.06 = 0.1176
 
  • Like
Likes KinzaFatima
Right.
It would be useful to keep the units everywhere, this gives a direct cross-check for your measurements.
 
physics604 said:
That's alright, I finally understand it now.

τ = Fl = 0.20x9.8x0.06 = 0.1176
Can you please explain me?
 
KinzaFatima said:
Can you please explain me?
he calculates the torque of the mass 0.20g with respect to the central axis of the coil.
 
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