Electron beam of a computer monitor

AI Thread Summary
The current in the electron beam of a computer monitor is 410 µA, which translates to 410 µC of charge striking the screen per second. To find the number of electrons hitting the screen, the calculation involves dividing the charge by the charge of a single electron, resulting in approximately 2.56 x 10^15 electrons per second. The initial attempt at calculation was incorrect due to a misunderstanding of exponent rules. Correctly applying these rules leads to the right answer, emphasizing the importance of careful calculations. Accurate exponent handling is crucial for solving such physics problems effectively.
JJones_86
Messages
72
Reaction score
0

Homework Statement


The current in the electron beam of a computer monitor is 410 µA. How many electrons per second hit the screen?


Homework Equations





The Attempt at a Solution


A beam current of 410µA means that 410µC of charge strike the screen per second. This is equivalent to (410e-6C)/(1.6×10-19C/e) = 6.56e-23 electrons...

But it's telling me that it's the wrong answer, any help is appreciated!
 
Physics news on Phys.org
I don't think you mean 10-23electrons
410 x10-6 / 1.6 x10-19 = 410/1.6 x10-6 - -19 = 250 x10-6 +19 = 250 x10+13

It's worth knowing the rules for doing calculations with exponents so you can estimate the answer before entering the numbers in a calculator
 
Last edited:
Oops, calculator error, thanks!
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top