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ToffeeCake
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Homework Statement
[PLAIN]http://img214.imageshack.us/img214/6328/physics2.jpg
An electron enters the lower left side of a parallel plate capacitor and exists precisely at the upper right side (just clearing the the upper plate). The initial velocity of the electron is 7x10^6 m/s parallel to the plates (see diagram). The capacitor is 2 cm long and its plates are separated by 0.150 m. Assume the electric field is uniform at every point between the plates and find its magnitude.
The correct answer is supposed to be 2.09x10^5 N/C.
Homework Equations
Electric Force Equation
The Attempt at a Solution
Since E= F/q, I attempted to find F by stating F=ma. To find acceleration, I said v=d/t thus t=d/v. Then a=v/t. I plugged this "a" into F=ma and used the mass of an electron to calculate force and then divided by the electron's charge, but I didn't get the right answer. Any suggestions?
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