Opus_723
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Homework Statement
The position of a proton at time t is given by the distance vector
\vec{r}(t) = \hat{i}x(t) + \hat{j}y(t) + \hat{k}z(t)
A magnetic induction field along the z-axis, \vec{B} = \hat{k}B_{z} exerts a force on the proton
\vec{F} = e\vec{v}\times\vec{B}
a.) For initial conditions:
x(0) = x_{0}
\dot{x}(0) = 0
y(0) = 0
\dot{y}(0) = v_{y0}
z(0) = 0
\dot{z}(0) = v_{z0}
and using cartesian coordinates calculate the orbit of the proton.
b.) Rephrase this entire problem in circular cylindrical coordinates and solve in circular cylindrical coordinates
The Attempt at a Solution
I think I managed to solve it in Cartesian by solving a coupled system of linear differential equations. My result was:
x(t) = \frac{v_{y0}m}{eB_{z}}cos(\frac{eB_{z}}{m}t) + (x_{0}-\frac{v_{y0}m}{eB_{z}})
y(t) = \frac{v_{y0}m}{eB_{z}}sin(\frac{eB_{z}}{m}t)
z(y) = v_{z0}t
But I don't see how to do this in cylindrical coordinates. When I set up the differential equations using Newton's Law, I get:
\ddot{\rho}-\rho\dot{\varphi}^{2} = \frac{eB_{z}}{m}\rho\dot{\varphi}
\rho\ddot{\varphi}+2\dot{\rho}\dot{\varphi} = \frac{-eB_{z}}{m}\dot{\rho}
\ddot{z} = 0
And of course the initial conditions
\rho(0) = x_{0}
\dot{\rho}(0) = 0
\varphi(0) = 0
\dot{\varphi}(0) = \frac{v_{y0}}{x_{0}}
z(0) = 0
\dot{z}(0) = v_{z0}
But those equations are nonlinear, and I don't see any way to do this problem, although I assumed the problem would be easier in cylindrical coordinates because of the symmetry involved. I can see how the solutions for \rho(t) and \varphi(t) could get really weird in the general case where the helix isn't centered on the z-axis. But I don't see how to simplify this particular problem.