Electron & Proton within a capacitor

AI Thread Summary
In a charged capacitor with a plate separation of 0.0800 m, a proton and an electron are released from rest at the midpoint. The challenge is to determine how far the proton travels by the time the electron strikes the positive plate, while ignoring their mutual attraction. The discussion highlights the need to calculate the acceleration of both particles and the time it takes for the electron to reach the plate. By applying kinematic equations, the user can find the distance traveled by the proton using the time derived from the electron's motion. Clarification on the concept of distance remaining for the proton was also addressed, emphasizing the importance of understanding the relationship between their accelerations.
Hannisch
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Homework Statement


"The plate separation of a charged capacitor is 0.0800 m. A proton and an electron are released from rest at the midpoint between the plates. Ignore the attraction between the two particles, and determine how far the proton has traveled by the time the electron strikes the positive plate."


Homework Equations


Not 100% sure.


The Attempt at a Solution


I've tried using energy conservation and Newton's Second Law and I've tried to have a look at every other equation I've been given and their derivations. I'm just stuck. I think there might be a conceptual part I'm missing?

If anyone could just give some hints, I'd be very grateful.
 
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Hannisch said:

Homework Statement


"The plate separation of a charged capacitor is 0.0800 m. A proton and an electron are released from rest at the midpoint between the plates. Ignore the attraction between the two particles, and determine how far the proton has traveled by the time the electron strikes the positive plate."

Homework Equations


Not 100% sure.

The Attempt at a Solution


I've tried using energy conservation and Newton's Second Law and I've tried to have a look at every other equation I've been given and their derivations. I'm just stuck. I think there might be a conceptual part I'm missing?

If anyone could just give some hints, I'd be very grateful.

Apparently the forces on each would be equal wouldn't they, even though in opposite directions?

But they have different mass. So ...
 
I get that mass of electron*acceleration of electron=mass of proton*acceleration of proton.

The thing is, I think I'm understanding what I should calculate wrong - somewhere in my mind I want to find the time it takes for the electron to hit the positive plate and from that find the acceleration of the electron (using x=at2/2) and using the relation between the electron's and the proton's accelerations and from there using previously mentioned equation to find the distance for the proton.

However I seem to have one too many variables constantly. I just don't know what I should do, it's driving me absolutely nuts.

And probably I'm making it more difficult than it is as well x|
 
You may just be making it more difficult than necessary.

The point is, figure the acceleration for each. You know the distance.

You remembered your kinematic equations for distance acceleration and time being:

x = 1/2*a*t2

Figure the time for the electron.
Then use that time with the proton acceleration to figure distance for the proton.

Subtract from the total distance and you have your Δ.
 
I get an answer that's something like .02 mm .. but I've recently learned that in electricity I'm perfectly useless in determining whether the answer is reasonable or not. But I found expressions for their accelerations (being Fc/m) and just .. used that expression. It works for me, at least.

The only thing I'm not sure about is what you mean by the delta - to me that seems to be figuring out how far it is left for the proton to hit the negative plate. However, I don't think I'm thinking clearly anymore, so I probably should drop it.

Thanks so much for your help! I really needed someone to hit me over the head and make me think about it the right way.
 
Never mind that about Δ. I mistakenly had it in mind they wanted to know how much further it had gone.
Sorry for any confusion my confusion may have caused.
 
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