Electrostatic induction (can someone check my answer?)

AI Thread Summary
The discussion revolves around the process of charge distribution among three identical metal spheres through electrostatic induction. Initially, the first sphere with charge q transfers q/2 to the second sphere upon contact, leaving it with q/2. The second sphere then transfers q/4 to the third sphere, resulting in the first sphere retaining q/4. Finally, when the third sphere touches the first again, the total charge on the first sphere becomes 3q/4, leading to a final charge distribution of 3q/8 on both the first and third spheres. The calculations and reasoning presented seem to be correct.
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Homework Statement


Three identical metal spheres are supported on three insulating stands.A charge q is given on the first sphere .The first sphere is then momentarily touched with the second sphere and then the second sphere is momentarily touched with the third.
Finally the third sphere is momentarily touched with the first again.
The final amounts of charge residing on the first,second and the third spheres respectively are...?


Homework Equations





The Attempt at a Solution



I think in the first case,
when the 1st sphere touches the 2nd,a charge of q/2 passes on to sphere 2 and a charge of q/2 remains on sphere 1
Then when sphere 2 touches sphere 3,a charge of q/4 moves to sphere3 and q/4 remains on sphere 1,
And when,sphere 3 touches sphere 1 again,the total charge is now q/2 + q/8 i.e 3q/4,
so sphere 1 and sphere 3 now have a charge of 3q/8 each ?

Thanks in advance !
 
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Looks OK to me.
 
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