Electrostatics of balls on a string

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SUMMARY

The discussion focuses on solving a physics problem involving two identical conducting balls with charge q, suspended by non-conducting threads of length L. The equilibrium separation of the balls is derived using the formula x=(q²L/(2πε₀mg))^(1/3). Given parameters include L=120 cm, m=10 g, and x=5.0 cm, leading to the calculation of the charge |q|. The application of Coulomb's law, F=(1/(4πε₀))(q₁q₂/r²), is essential for understanding the forces at play in this scenario.

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  • Understanding of forces and their components (vertical and horizontal)
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Yuravian
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Homework Statement


In Fig. 21-42 (I attached an MSPaint rendition of it), two tiny conducting balls of identical mass m and Identical charge q hang from non-conducting threads of length L. Assume [tex]\theta[/tex] is so small that [tex]tan \theta[/tex] can be replaced by its approximate equal, [tex]sin \theta[/tex]. (a) Show that [tex]x=(\frac{q^2L}{2\pi\epsilon_{0}mg})^{1/3}[/tex] gives the equilibrium separation of the balls. (b) If L=120cm, m=10 g, and x=5.0 cm, what is |q|?


Homework Equations


Well, I think Coulomb's law is clearly involved because of the [tex]\frac{1}{2\pi\epsilon_{0}}[/tex] bit, which is equal to 2*k.
So then, restating Coulomb's law: [tex]F=\frac{1}{4\pi\epsilon_{0}}*\frac{\left|q_1\right|\left|q_2\right|}{r^2}[/tex]

The Attempt at a Solution


The problem here is I don't know how to start the problem. It appears simple enough but I can't seem to get an answer out of it. Here is what I was thinking: since [tex]q_1[/tex] and [tex]q_2[/tex] are both the same, the top bit of coulomb's law becomes [tex]q^2[/tex] since any number squared is positive (no need for abs. value). splitting out coulomb's law from the full equation within parenthesis gives [tex]x=(\frac{1}{4\pi\epsilon_{0}}*\frac{q^2}{r^2}*\frac{2Lr^2}{mg})^{1/3}[/tex]. The problem with this is that I had to work in [tex]\frac{r^2}{r^2}[/tex], when I'm pretty sure there's an equivalency in there somewhere.
 

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Pick one of the balls (the left one, say) and analyze the forces acting on it. The Coulomb force is just one of the forces involved. Hint: Consider vertical and horizontal components separately.
 

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