1. The problem statement, all variables and given/known data A farsighted woman breaks her current eyeglasses and is using an old pair whose refractive power is 1.655 diopters. Since these eyeglasses do not completely correct her vision, she must hold a newspaper 39.4 cm from her eyes in order to read it. She wears the eyeglasses 1.90 cm from her eyes. How far is her near point from her eyes? 2. Relevant equations 1/f = 1/(do) + 1/(di) di < 0 for virtual images (what this is) 3. The attempt at a solution do is .394m and 1/f=1.655 diopters so 1/(1/.394m - 1.655) = di di = 1.13m Near Point = 1.13m + .019m = 1.15m Where did I go wrong? Thanks!