Elevator going down and you drop a book

In summary, the book will take 3.834 seconds to reach the elevator floor and its speed upon impact will be 0.1437 m/s. The correct equations to use for this problem are the kinematic equations.
  • #1
kmiller
15
0

Homework Statement



While riding on an elevator descending with a constant speed of 3.3 m/s, you accidentally drop a book from under your arm.
(a) How long does it take for the book to reach the elevator floor, 1.1 m below your arm?
s
(b) What is the book's speed (relative to the earth) when it hits the elevator floor?


The Attempt at a Solution



4.9m/9.8m/s2=14.7
squareroot 14.7=3.834=answer a

1.1m+1/2(13.1)t
t=7.65
1.1m/7.65s=.1437=answer b

both of these answers were wrong. what equations am ia supposed to use?
how do i start?
 
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  • #2
For the first part it looks as though you're trying to use the correct equation but I have no idea where you got your numbers from?

For part b it will just be the speed of the elevator added to the speed you work out from standard kinematic equations.
 
  • #3


As a scientist, it is important to first identify the relevant physical principles and equations that can be applied to this scenario. In this case, we can use the equations for kinematics, specifically the equations for motion with constant acceleration. The relevant equations are:

1. Distance traveled, d = v0t + 1/2at^2
2. Final velocity, vf = v0 + at
3. Average velocity, vavg = (v0 + vf)/2

In this scenario, we can assume that the book is initially at rest (v0 = 0) and is dropped from a height of 1.1 m. We also know that the elevator is descending with a constant speed of 3.3 m/s, so the acceleration due to gravity (a) is equal to 3.3 m/s^2.

(a) Using the first equation, we can solve for the time it takes for the book to reach the elevator floor:

1.1 m = 0 + 1/2(3.3 m/s^2)t^2
t = √(2(1.1 m)/3.3 m/s^2) = 0.67 s

Therefore, it takes 0.67 seconds for the book to reach the elevator floor.

(b) To find the book's speed when it hits the elevator floor, we can use the second equation:

vf = 0 + (3.3 m/s^2)(0.67 s) = 2.21 m/s

This means that the book's speed (relative to the earth) when it hits the elevator floor is 2.21 m/s.

It is important to carefully select and apply the correct equations and units in order to obtain accurate and meaningful results in any scientific calculation.
 

1. What happens to the book when the elevator goes down?

When the elevator goes down, the book will experience a downward force due to the acceleration of the elevator. This force will cause the book to also accelerate downwards, and it will appear to drop to the floor.

2. Why does the book drop in an elevator going down?

The book drops in an elevator going down because of the force of gravity. When the elevator accelerates downwards, the book experiences a greater downward force than the floor of the elevator, causing it to drop.

3. Does the weight of the book affect how fast it drops in an elevator going down?

Yes, the weight of the book does affect how fast it drops in an elevator going down. The heavier the book, the greater the force of gravity, and the faster it will accelerate towards the floor of the elevator.

4. Will the book drop at the same rate as the elevator in free fall?

No, the book will not drop at the same rate as the elevator in free fall. While both the book and the elevator are falling towards the ground, the elevator is designed to slow down and stop at a certain floor, whereas the book will continue to accelerate downwards until it reaches the floor of the elevator.

5. Is it safe to drop a book in an elevator going down?

It is generally safe to drop a book in an elevator going down. However, it is important to be cautious and considerate of others in the elevator. Dropping a heavy or sharp object could potentially cause harm to other passengers or damage to the elevator. It is always best to handle objects carefully while in an elevator.

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