Eliminating Alcohols: Why Do (A) and (B) Give Different Products?

AI Thread Summary
The discussion centers on the differing products formed from reactions (A) and (B) involving alcohol elimination. Reaction (A) yields both 1-pentene and 2-pentene, including its E-Z diastereomers, resulting in three possible products. In contrast, reaction (B) produces only the E and Z diastereomers of 2-pentene, leading to two possible products. The confusion arises from a discrepancy in expected product designations, with the original source indicating (A) leads to a different stereochemical outcome than anticipated. The participants express skepticism about the reliability of the source material, questioning the accuracy of the provided information.
baldbrain
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Homework Statement
I just have a problem with (A) & (B)
IMG_20180719_173721.JPG

The attempt at a solution
Analysing all possible products;
(A) can give 1-pentene (minor) + 2-pentene (major). But you also have the E-Z diastereomers of 2-pentene. So that's total 3 possible products.
(B) will give only the diastereomers E & Z 2-pentene. So 2 possible products
Hence, (A)→(s) & (B)→(r)
But they've given (A)→(r) & (B)→(s)
How can it be?
 

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Books are not infallible.
 
Are you sure? No hitch? We aren't missing anything?
 
Nope. S, R, Q, P.
 
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