Emergency Braking: Stopping Distance of 48m

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An automobile traveling at 16 m/s requires a total stopping distance of 48 meters when factoring in a driver reaction time of 1 second and a braking acceleration of 4.0 m/s². During the reaction time, the car covers 16 meters. The braking distance is calculated using the equation V² - V₀² = 2ax, resulting in an additional 32 meters needed to stop. The combined distance of 16 meters during reaction and 32 meters while braking totals 48 meters. This calculation confirms the stopping distance required for the given conditions.
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Homework Statement


An automobile is traveling at 16 m/s. The driver perceives a need to stop and applies the
brakes producing a (negative) acceleration of 4.0 m/S2. Take the reaction time of the
driver, the time to move from the go pedal to the stop pedal, as 1,0 s.

Homework Equations


How far does it take for the car to stop?

The Attempt at a Solution


during his reaction time, he traveled d=16*1=16m.
we calculate the distance of braking:
V2-V02=2*a*x
x= 32m.
the whole distance is 16+32=48m and that's what we have been asked to find.
 
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