potential energy is the energy of storage.
But moving objects store kinetic energy don't they? So the "energy of storage" for a moving object would be
kinetic.
You didn't answer the question though:
You told me about potential energy - not potential, which is what I asked for.
You gave me a description instead of a definition.
I think you are getting confused because you do not know what "potential" or "potential energy" is.
You should review your class notes on this topic - I can only go briefly here.
Definition:
Potential Energy of an object at a position is the amount of
work needed to get the object to that position from some agreed-upon reference position (usually an infinite distance away).
Thus, if we know ##\vec F(\vec r)##: how force varies with position, the work to move a small distance ##\text{d}\vec r## is ##dW=\vec F(\vec r)\cdot\text{d}\vec r##. Which needs vector calculus - which is why, when you start out, we just tell you the result.
example:
Gravitational Potential Energy of a mass at a position is the amount of work done to get that mass to that position from an infinite distance away.
Potential is the potential energy per unit <something> - where the <something> is the property of the object that is important to the potential energy.
example:
the important property for gravity is mass so -
Gravitational Potential is the gravitational potential energy divided by the mass.
For gravity - the force on mass m a distance r from mass M is $$\vec F(r)=-\frac{GMm}{r^2}\hat{r}$$
The potential energy of mass m at that distance is the work needed to get it there from infinitely far away.##\renewcommand{\dr}{\;\text{d}r}##
The work needed to bring the mass m to distance r is given by: $$U(r)=-\int_\infty^r F(r^\prime)\dr^\prime = -\frac{GMm}{r}$$The gravitational potential associated with distance r is U/m: $$\phi = \frac{GM}{r}$$.In electrostatics - we have to deal with having two charges ... so the general definition for potential energy is changed a bit.
Charges get a bit more ticklish because there are two kinds, but we can follow the definition:
Electrostatic Potential Energy of a charge q distance r from another charge Q is: $$U=\frac{kQq}{r}$$ ... if they are both positive charges or both negative charges, the U is positive (because the force is repulsive, you have to do work on the charge q to get it there).
Electrostatic Potential for distance r due to charge Q is U/q: $$\phi=\frac{kQ}{r}$$
A chage in potential would involve a change in position (final - initial) like this: $$\Delta\phi = kQ\left(\frac{1}{r_2}-\frac{1}{r_1}\right)$$ and the change in potential energy is related as follows: $$\Delta U = q\Delta\phi$$ ... so the answer to your question (back in post #1)
How do you figure that out?
...You put the numbers into the equation.
When a negative charge moves from a point of higher potential to a lower potential will it gain or lose PE?
If the change in potential is negative, and the charge is negative, then the charge has gained PE.
If the change in potential is positive, and the charge is negative, then the charge has lost PE.
If the charge has moved from a high potential to a low potential ... then ##\phi(r_2)>\phi(r_1)\implies \Delta\phi < 0## ... the change in potential is
negative. Then the charge has
gained potential energy.
Also what is the correlation between kinetic energy and potential energy?
If the charge q were moving freely (no other forces), then it slowed down - losing kinetic energy.