Energy and rate of energy transmitted by a given wave function

AI Thread Summary
The average rate of energy transmitted along the string is calculated to be 14,660.27 watts, based on the given wave function and linear mass density. The energy contained in each cycle of the wave is determined to be -2.67 joules, with the negative sign indicating the direction of energy transmission. The calculations utilize the relationships between power, energy, wave parameters, and linear mass density. Key formulas include P = (1/2)uw²A²v for power and E^ = (1/2)uw²A²λ for energy per cycle. Overall, the analysis provides insights into wave energy dynamics on a taut string.
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1.
The wave function for a wave on a taut string is given below, where x is in meters and t is in seconds.

y(x, t) = (0.300 m) sin(11πt - 3πx + π/4)​

(a) What is the average rate at which energy is transmitted along the string if the linear mass density is 75.0 g/m?

(b) What is the energy contained in each cycle of the wave?


2.
y(x,t) = Asin(kx-wt+phi)
E^ = (1/2)uw2A2^
P = E^/T = (1/2)uw2A2v
k = 2π/^
v = w/k
w = 2π/T = 2πf

A=amplitude, phi=phase contstant
E^=total energy in one wavelength, u=linear mass density, ^=wavelength
P=power, T=period,
k=wave#
v=velocity
w=angular frequency, f=frequency


3.
given: y(x,t) = (0.300 m) sin(-3πx + 11πt + π/4), therefore A = 0.3m, k = -3π, w = -11π, phi = π/4; u = 75g/m

(a)
P = (1/2)uw2A2v and v = w/k
therefore:
P = (1/2)(75g/m)(-11π)2(0.3m)2(-11π/-3π)
P = 37.5*121π2*0.09(11/3) = 14660.2709

P = 14660.27W

(b)
E^ = (1/2)uw2A2^ and k = 2π/^ so ^ = 2π/k
therefore:
E^ = (1/2)(0.075kg/m)(-11π)2(0.3)2(2π/-3π)
E^ = 0.0375*121π2*0.09(2/-3) = -2.6655038

E^ = -2.67J
 
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(negative sign indicates energy is being transmitted in the opposite direction)

Therefore, the average rate at which energy is transmitted along the string is 14660.27 watts and the energy contained in each cycle of the wave is -2.67 joules.
 
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