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qswdefrg
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Homework Statement
the small mass m sliding without friction along the looped track is to remain on the track at all times, even at the very top of the loop of radius r.
a) calculate, in terms of the given quantities, the min. release height h.
if actual release height is 2h, calculate
b) normal force exerted by track at bottom of loop
c) normal force exerted by track at top of loop
d) normal force exerted by track after block exits loop onto flat section
Homework Equations
Ek = 0.5mv^2
Eg = mgh
Fc = mv^2/r
The Attempt at a Solution
a) total energy = mgh
mass must remain on track at top of loop, so
mgh = 0.5mv^2 + mg(2r)
h = 2.5r
b) Does the release height matter? Because if mass does not accelerate up nor down, then Fn =mg? Is this the same for d)?
c) Centripetal force keeps mass moving
Fn = mv^2/r - mg
Fn = m(v^2/r - mg)
I'm not sure if this is right either.
any pointers/hints would be greatly appreciated.