Energy Density of Blackbody Radiation

[stefan10]

Homework Statement

\mbox{Let} \ p(< \nu_{0}) \mbox{be the total energy density of blackbody radiation in all frequencies less than} \ \nu_{0}, \mbox{where} \ h \nu_{0} << kT. \mbox{Derive an expression for} \ p (< \nu_{0})

Homework Equations

p(v) dv = \dfrac{8 \pi h} {c^3} \dfrac {\nu^3}{e^\frac{h\nu}{kT} -1} dv

The Attempt at a Solution

We want to find the total energy density, so that means we'll have to integrate the Planck's Law. The limits of integration will be from 0 to v-knot.

h \nu < h \nu_{0} << KT \Rightarrow h \nu << KT

Which if we simplify for this limit gives:

p(v) dv = \dfrac{8 \pi h} {c^3} \dfrac {\nu^3}{e^\frac{h\nu}{kT} -1} dv

p(v) dv = \dfrac{8 \pi h} {c^3} \dfrac {\nu^3}{\dfrac{h\nu}{kT} +1 -1} dv

p(v) dv = \dfrac{8 \pi h} {c^3} \dfrac {\nu^3}{\frac{h\nu}{kT} } dv

p(v) dv = \dfrac{8 \pi KT}{c^3} \nu^2 dv \ \mbox{Rayleigh-Jeans Formula}

p(<v_{0}) = \dfrac{8 \pi KT}{c^3}\int _ {0} ^{\nu_{0}} \nu^2 dv

p(<v_{0}) = \dfrac{8 \pi KT}{3 c^3}\nu_{0}^3

Is there anything wrong? Thank you very much!

 

[TSny]

Looks good to me.