From _Physics_, Wolfson and Pasachof, ISBN 0-673-39836-6, p. 1055:
E = h^2/8mL^2 (n^2 sub x + n^2 sub y + n^2 sub z)
CW
#3
cytochrome
163
3
Thank you, now what do I use for the n_x, n_y, n_z?
#4
psmt
38
1
Hint: try substituting separable sinusoidal solutions into the Schrodinger eqn (with suitable boundary conditions).
#5
ssamsymn
18
0
n_x , n_y , n_z are your quantum numbers, they describe your state, when you solve the Schr. Eqn. for ψ's, which are sinusoidal functions as mentioned below, n_x,y,z will appear in the energy values.
Insights auto threads is broken atm, so I'm manually creating these for new Insight articles.
Towards the end of the first lecture for the Qiskit Global Summer School 2025, Foundations of Quantum Mechanics, Olivia Lanes (Global Lead, Content and Education IBM) stated...
Source: https://www.physicsforums.com/insights/quantum-entanglement-is-a-kinematic-fact-not-a-dynamical-effect/
by @RUTA
If we release an electron around a positively charged sphere, the initial state of electron is a linear combination of Hydrogen-like states. According to quantum mechanics, evolution of time would not change this initial state because the potential is time independent. However, classically we expect the electron to collide with the sphere. So, it seems that the quantum and classics predict different behaviours!
The wavefunction of an atomic orbital like ##p_x##-orbital is generally in the form ##f(\theta)e^{i\phi}## so the probability of the presence of particle is identical at all the directional angles ##\phi##. However, it is dumbbell-shape along the x direction which shows ##\phi##-dependence!