Energy Lost During Purely Inelastic Collisions

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SUMMARY

The discussion centers on the mathematical analysis of energy loss during purely inelastic collisions, specifically applying conservation of momentum principles. The kinetic energy loss during such collisions is directly related to the deformation and smashing of the colliding objects. The energy lost can be quantitatively expressed using the formula ΔE = ½μΔv², where μ represents the reduced mass and Δv denotes the relative velocity of the objects. The conversation also highlights that the material properties of the colliding bodies influence the conditions under which inelastic collisions occur.

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  • Familiarity with kinetic energy calculations
  • Knowledge of material properties related to stress-strain curves
  • Basic grasp of inelastic collision dynamics
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jon4444
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I'm curious about how the math comes out when you apply conservation of momentum to the theoretical problem of a moving object having a purely inelastic collision with another stationary object in a single dimension. Since the velocity of the combined object is entirely determined by the initial speed of the moving object and the masses of the objects, these parameters also determine the amount of energy lost (when you compare the kinetic energy of the initial object versus that of the combined object).
But shouldn't energy loss be related to how much smashing and deformation goes on during the collision? Is there another interpretation I'm missing?
 
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jon4444 said:
I'm curious about how the math comes out when you apply conservation of momentum to the theoretical problem of a moving object having a purely inelastic collision with another stationary object in a single dimension. Since the velocity of the combined object is entirely determined by the initial speed of the moving object and the masses of the objects, these parameters also determine the amount of energy lost (when you compare the kinetic energy of the initial object versus that of the combined object).
But shouldn't energy loss be related to how much smashing and deformation goes on during the collision? Is there another interpretation I'm missing?
You have assumed that the two objects smash together and then continue to move together as one object. The energy lost to the smashing and deformation required to reach that state is exactly equal to the kinetic energy loss.
 
jon4444 said:
these parameters also determine the amount of energy lost (when you compare the kinetic energy of the initial object versus that of the combined object).
Yes.

jon4444 said:
shouldn't energy loss be related to how much smashing and deformation goes on during the collision?
Yes. The two amounts are the same.
 
But shouldn't energy loss be related to how much smashing and deformation goes on during the collision?
But shouldn't smashing and deformation be related to energy loss? Or even, determined by it.
 
so, say certain materials require a certain amount of energy to join together (the smashing and deformation)--this essential sets a critical condition for if you could have an inelastic condition (i.e., only under certain relative masses and initial speed).
Is that a correct interpretation of the situation?
 
jon4444 said:
so, say certain materials require a certain amount of energy to join together (the smashing and deformation)--this essential sets a critical condition for if you could have an inelastic condition (i.e., only under certain relative masses and initial speed).
Is that a correct interpretation of the situation?
Yes, for example, if a material has an elastic region and a plastic region in its stress strain curve then you would not get a plastic collision at low energies.
 
Since the OP asked about the maths, then (for the record) energy loss in a perfectly inelastic collision is given by:

## ΔE = ½μΔv^2 ##

where μ is the reduced mass of the colliding objects and Δv their relative velocity.
 
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