Energy per second transferred by the resultant wave

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SUMMARY

The energy transferred per second by a progressive wave is directly proportional to the square of its amplitude, as established in wave mechanics. When two waves are in phase and superposed, the energy per second transferred by the resultant wave is proportional to the sum of their amplitudes squared, confirming that the correct answer is B. The discussion emphasizes the importance of understanding the vector sum of individual displacements to derive the correct relationship for energy transfer in waves.

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  • Understanding of wave mechanics and energy transfer
  • Familiarity with the concept of amplitude in waves
  • Knowledge of vector addition in physics
  • Basic mathematical treatment of proportional relationships
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  • Study the relationship between amplitude and energy transfer in waves
  • Learn about the superposition principle in wave mechanics
  • Explore mathematical proofs involving wave energy calculations
  • Investigate the implications of phase relationships in wave interactions
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Students studying wave mechanics, physics educators, and anyone interested in understanding energy transfer in mechanical waves.

desmond iking
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Homework Statement


the energy transferred per second by a progressive waves is directly propotional to the square of its amplitude, if two waves are in phase and superposed, the energy per second transferred by the resulatant wave propotional to A.) the sum of amplitude. B). The diffrenece of the amplitudes.


Homework Equations





The Attempt at a Solution



my ans is A. since when two waves superposed at a pointy, the resultant displacement is vector sum of individual displacement of two waves. BUT the ans given is B .
 
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So how would you go about proving that you are right?
Maybe a mathematical treatment?
 
Simon Bridge said:
So how would you go about proving that you are right?
Maybe a mathematical treatment?

i am not saying i am right. just based on the reason the resultant displacement is vector sum of individual displacement of two waves. i chose A. so am i correct?
 
Neither A) nor B) seem correct to me. May be I misunderstand the question?
 
desmond iking said:
i am not saying i am right. just based on the reason the resultant displacement is vector sum of individual displacement of two waves. i chose A. so am i correct?
You have said that the model answer says the correct answer is (B) - you did not put that, so you were marked incorrect.
The question only arises if you suspect the model answer is wrong - so you were marked down unfairly.

Therefore, your problem is that you need to find some way to show that the model answer is incorrect, or, failing that, to confirm the model answer is indeed correct.

Your reasoning, how you would go about showing that you are correct, or that they are correct, or whatever, will help us figure out how best to help you.

I'll start you off - you are told that the energy per second of a wave is proportional to the amplitude squared. You write this is as: $$P\propto A^2$$

You are told that two of these waves are in phase - so what is the amplitude of the combined wave?
If the combined wave obeys the same power-amplitude relationship as individual waves, what is the rate of energy transfer for the combined wave?

Please bear in mind that me just telling you if you are correct amounts to telling you the answer - which is against the forum rules.
 
Last edited:
@Dauto: I could make a case either way - the question seems to be from the UK A-level curriculum referring to mechanical traveling waves. Students will have been expected to use their understanding of the coursework to answer the question - which is why it seems a bit incomplete and glib. Either that or we don't have the full text here.

I want to see OPs reasoning before giving away the answer.
 

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