Calculate Work, Power, PE and KE for a 400W Motor

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To calculate the work done by a 400W motor running on 240V for 200 seconds, the formula Work = Power x Time is used. The current drawn by the motor can be determined using Power = IV. To find the time required to raise a 15kg mass vertically 5 meters, the relationship between work and energy must be applied. Potential energy can be calculated using the formula PE = mgh, confirming its correctness. For the velocity after falling 3.5 meters, the formula v^2 = u^2 + 2as is appropriate to determine the final velocity.
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I have a question where I am given watts, voltage and time. Let's say the electric motor is 400 watt that is run from 240v mains electricity for 200seconds.

I have managed to calculate the work done using the formula Work done (J) = Power (W) x time taken (J) And I have managed to calculate the current the motor uses using the formula Power = IV.

I have no idea how I would calculate how long it takes for the pulley system to raise 15kg mass vertically 5 metres when the motor is connected to the pulley.

I am also asked to calculate the PE of the fully raised mass, I assume here I would use this formula;

Potential= mgh (Am I right?)

How do I calculate it's velocity after falling for 3.5 metres? Do I use this formula? KE= 1/2 MV^2

Thanks.
 
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The motor's power is given. As you mentioned, Energy = Power X Time and Potential Energy = m g h.
 
edgepflow said:
The motor's power is given. As you mentioned, Energy = Power X Time and Potential Energy = m g h.

I figured how to work out but the others.
 
How do I calculate it's velocity after falling for 3.5 metres?

d = v0t + 1/2at2
 
The total Energy is constant: KE + PE = constant. If one goes down, the other goes up.
 
Naty1 said:
How do I calculate it's velocity after falling for 3.5 metres?

d = v0t + 1/2at2

But if I rearrange the formula (making v0 the subject) it will only give me the original velocity and not the velocity is is at after 3.5 metres. Are saying that after finding this I should use; v^2 = u^2 + 2as to find the velocity at 3.5 metres?

how I would calculate how long it takes for the pulley system to raise 15kg mass vertically 5 metres when the motor is connected to the pulley.
 
Hi, Could someone please help me out.
 
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