Energy related problem (includes diagram)

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SUMMARY

The discussion centers on calculating the work done by a force on a box being pulled at an angle. The force applied is 176 N at an angle of 38 degrees, and the mass of the box is 88 kg. The correct expression for work must account for the angle, leading to the formula W = F * d * cos(θ). The user initially calculated work without considering the angle, resulting in incorrect values for both work and velocity.

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Homework Statement


A box m = 88 kg is being pulled by a constant force F = 176 N at an angle of θ = 38 degrees.

m = 88 kg
θ = 38 degrees
F = 176 N

Homework Equations



W=Fd

The Attempt at a Solution



(a) Write an expression for the work done by force F on the block over a distance d.

Okay, so for this one I just put in W=Fd. The problem started out with "W=" before showing the blank right next to it, so I assumed it just wanted the work equation. However, this is wrong. I'm not exactly sure how else to figure it out.

(b) How much work, in Joules, was done in moving the block 5 meters?

So I did W=Fd again. I multiplied 176*5, got a value of 880 J. Apparently this is wrong, too. Why? Do I need to factor in the angle in which block is being pulled?

(c) What is the velocity of the box at d = 5 m if the surface is frictionless?
I'm aware that the equation needed to solve for this is W = mv2/2, since it allows me to solve for velocity, however I don't have that, nor do I have W because I'm guessing that the problem assumes that I need to use the value I got for W in order to solve this problem.

Any help will be very much appreciated.
(See attachment for diagram)
 

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Ah, that made the problem so much easier. Thank you!
 

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