How Much Energy Is Released from 1kg of Deuterium in Fusion?

AI Thread Summary
The discussion centers on calculating the energy released from 1 kg of deuterium during fusion, specifically when two deuterium atoms fuse to form tritium and hydrogen. The energy produced is stated to be 3.89 MeV per fusion event. Participants clarify the calculations, noting the use of factors like 0.5 and division by 2 to account for the number of deuterium atoms involved. One user corrects their initial calculation, arriving at a result close to 5.80 x 10^26 MeV. The conversation emphasizes the importance of accurately interpreting the molar mass and energy equations in fusion calculations.
desmond iking
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Homework Statement


Two 2_1 H atoms undergo fusion to form 3_1 H and 1_1 H atom
calculate the energy released by 1.0kg of deuterium..
the amu is given as :2_1 H : 2.01402u
3_1 H : 3.016049u
1_1 H : 1.007825 u
P/s : i am sure that the energy produced is 3.89MeV ...

Homework Equations

The Attempt at a Solution


0.5 x (1000/2) x 6.02x10^23 x 3.89MeV = 5.85x10^26 MeV

Is my working correct?
 
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Why both the 0.5 and the /2?
I get exactly double your answer by calculating the fraction of mass lost, then the total mass lost, then using E=mc2.
 
0.5 means there' re 2 H atom /2 means mrr 2g... I am calculating the energy released for 1 H atom...
 
So I divide 2
 
desmond iking said:
So I divide 2
Yes, but why twice (0.5, then /2)?
 
Mrr is 2g. And there re 2 H atom sow I divide 2 twice
 
desmond iking said:
Mrr is 2g. And there re 2 H atom sow I divide 2 twice
Sorry, you've lost me. What are Mrr and 2g in this context?
 
haruspex said:
Sorry, you've lost me. What are Mrr and 2g in this context?
molar mass of deuterium= 2g
 
Last edited:
desmond iking said:
molar mass of deuterium= 2g
Ah, OK. I didn't recognise it because you truncated it from the given 2.01402.
I've found the mistake in my own working and now get almost the same as you do: 5.80E26.
 
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