Energy Required to Change Water into Steam

AI Thread Summary
To convert one-quarter of 8.0 kg of water at 25°C into steam, the total energy required is calculated by first raising the temperature of all the water to 100°C and then converting 2.0 kg to steam. The specific heat capacity of water is 4200 J/kg°C, and the latent heat of vaporization is 2.3 x 10^6 J/kg. The total energy calculation yields Q total = 7.12 x 10^6 J. The approach taken in the calculations is confirmed to be correct. This demonstrates the energy requirements for phase changes in water.
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Homework Statement



How much energy is required to change one-quarter of 8.0kg of water at 25 C into steam?

The way I see it, the entirety of the 8.0kg of water must be brought from 25 C to 100 C, then only 2.0kg is changed to steam so...

Specific heat capacity (of water) = 4200 J / kg C
Latent heat of vaporization (of water) = 2.3 * 10^6 J/kg

Q total = (8.0kg) (4200 J / kg C) (100-25) + (2.0kg) (2.3 * 10^6 J/kg)
Q total = 7.12 * 10^6 J

I'm not 100% sure if I'm doing this properly. Does this look correct?
 
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That looks correct to me!
 
Cool, thanks!
 
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