Energy stored in a single capacitor

  • Thread starter Thread starter lat77
  • Start date Start date
  • Tags Tags
    Capacitor Energy
AI Thread Summary
The discussion revolves around calculating the energy stored in a capacitor network with a potential difference of 12.0V. The total energy stored in the network has been determined to be 158 μJ. To find the energy stored in the 4.80 μF capacitor, the relationship between charges in a series capacitor circuit is emphasized, noting that the charge is the same across all capacitors in series. The equivalent capacitance of the circuit is calculated to be 2.18 μF, and the relationship between individual charges and the total charge is explored. Understanding these relationships is crucial for solving the problem correctly.
lat77
Messages
6
Reaction score
0

Homework Statement


For the capacitor network shown in the Figure (Figure 1) , the potential difference across is 12.0 . (Figure is attached by the way)
A)Find the total energy stored in this network. (I already found this to be 158 μJ)
B)Find the energy stored in the 4.80- capacitor.


Homework Equations


U=1/2 CV^2


The Attempt at a Solution


I would imagine that you need to subtract the amount of energy in the parallel branches from the total amount of energy of the system, but I don't know how to do this without knowing the charge.
 

Attachments

  • YF-24-57.jpg
    YF-24-57.jpg
    6.4 KB · Views: 588
Physics news on Phys.org
Another equation that I would add to your list is Q = CV (Charge = Capacitance x voltage).

I will give you a hint in the form of two questions:
1) How are the charges in a series capacitor circuit related?
2) How does the charge on one of the capacitors in a series capacitor circuit related to the total charge in the circuit?
 
misterc said:
Another equation that I would add to your list is Q = CV (Charge = Capacitance x voltage).

I will give you a hint in the form of two questions:
1) How are the charges in a series capacitor circuit related?
2) How does the charge on one of the capacitors in a series capacitor circuit related to the total charge in the circuit?

1) Q=CV as your equation said.
2) (Qtotal/#of capacitors)=Charge per capacitor?
 
Since you got part a), I'll assume you can convert between series, parallel and total capacitance.

So, in your problem, we can model the circuit as three capacitors in series. Correct?

Let's call the three capacitors C1, C2, C3 where C1 = 8.6 uF, C2 = 4.8 uF, and C3 = 7.5 uF. Correct?

Let's call Ceq the total equivalent capacitance = 2.18 uF. Correct?

My questions then are:
How are Q1, Q2, and Q3 related?
How does Q2 (since that's the capacitor in question), relate to Qeq?
 
Thread 'Voltmeter readings for this circuit with switches'
TL;DR Summary: I would like to know the voltmeter readings on the two resistors separately in the picture in the following cases , When one of the keys is closed When both of them are opened (Knowing that the battery has negligible internal resistance) My thoughts for the first case , one of them must be 12 volt while the other is 0 The second case we'll I think both voltmeter readings should be 12 volt since they are both parallel to the battery and they involve the key within what the...
Thread 'Trying to understand the logic behind adding vectors with an angle between them'
My initial calculation was to subtract V1 from V2 to show that from the perspective of the second aircraft the first one is -300km/h. So i checked with ChatGPT and it said I cant just subtract them because I have an angle between them. So I dont understand the reasoning of it. Like why should a velocity be dependent on an angle? I was thinking about how it would look like if the planes where parallel to each other, and then how it look like if one is turning away and I dont see it. Since...

Similar threads

Back
Top