Engineering Economics Present Worth

AI Thread Summary
The discussion focuses on calculating the Net Present Worth (NPW) for three alternatives in an engineering economics problem, with given initial costs, annual benefits, and useful lives. The alternatives include X with a high initial cost but significant annual benefits, Y with a low initial cost and infinite life, and Z with moderate costs and benefits. The participant successfully calculated the NPW for alternative Y but encountered difficulties with X and Z. A typo in the problem was identified, which contributed to the confusion. The discussion emphasizes the importance of accurate data in engineering economic analysis.
MHrtz
Messages
53
Reaction score
0

Homework Statement



Three different alternatives shown below are being considered. Assume that alternatives X and Z are replaced at the end of their lives


Alt. X Alt. Y Alt. Z
Initial Cost - 6000 1000 1500

Annual Benefits - 810 125 230

Useful Life - 20 infinite 10

MARR = 12% for all

Find the Net Present Worth for Alt. X, Alt. Y, and Alt. Z.

Homework Equations



capitalized cost A = iP

F = A [((1 + i)n - 1))/i]

P = A [((1 + i)n - 1))/i(1 + i)n]

The Attempt at a Solution



I found the NPW for Alt. Y

P = (125/.12) - 1000 = 41.67

I'm still stuck on X and Z.
 
Physics news on Phys.org
Nevermind. One of choices was a typo so I got it right.
 
Back
Top