Engineering Statics Center of Gravity Problem

AI Thread Summary
The discussion revolves around locating the x-coordinate of the center of gravity for a machine element involving triangles. The user is confused about the calculation for problem 96, specifically why the solution uses 2/3*66 + 34 instead of 1/3*66 + 34 as seen in problem 98. Clarification is sought on the method for determining the center of gravity for triangles, with a suggestion to draw a plan of the triangle to find the position of G. The user also inquires if the same approach applies to the y-component. Understanding the geometric properties of the triangle is essential for solving the problem accurately.
ttran1117
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Homework Statement


For the machine element shown, locate the x coordinate of the center of gravity.
The picture of 2 different problems are attached

Homework Equations


V = 1/3*a*b*h


The Attempt at a Solution


I can figure out the coordinates fine for everything except the triangles. I looked at the solution for problem 96 and I can't seem to figure out why the solution is 2/3*66 + 34 (coordinate). I understand that the base would be x/3, or 66/3, which is true for problem 98, so why isn't it problem 96 using 34+ 1/3*66 and instead is using 34 +2/3*66? Any help would be greatly appreciated, as I have spent a long time on this and can't seem to figure it out. Also, would this be same for the y component as well? Thank you very much
 

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I think the triangle you speak of is the 'empty' triangle in the xz plane. What is the x-coordinate of its centre of gravity? To check this, draw a plan of the triangle and obtain the position of G by joining the mid point of each side to its opposite corner. Hopefully this is enough for the penny to drop.
 

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