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Entropically or Enthalpically favorable?

  1. Sep 22, 2008 #1
    1. The problem statement, all variables and given/known data
    6CO2 + 6 H2O → C6H12O6 + 6 O2

    2. Relevant equations

    3. The attempt at a solution
    I believe that this is entropically and enthalpically unfavorable because the reaction is going to more order (synthesis of glucose) and heat is not being generated.

    Is my logic correct? Thanks anyone for any help you can give me.
  2. jcsd
  3. Sep 22, 2008 #2


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    Somewhat ... you've got more molar gas on the left , in addition this is a reverse combustion reaction , you should know that it is combustion reactions that are exothermic.
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