lavster
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can someone confirm that the equation for the linear energy transfer is:
LET=-\frac{4\pi e^4Nz^2Z}{m_0v^2} (ln\frac{2m_0v^2}{I}-ln(1-\beta^2)-\beta^2)=-\frac{dE}{dx},
where e is the charge of an electron, Z is the atomic number of the material being irradiated, m_0 is the mass, z is the charge number of the beam particle, v is the velocity of the beam particle, I is the average ionisation potential (\approx11.5Z(eV)), \beta=\frac{v}{c} and \frac{dE}{dx} is the energy loss per unit length.
and hence LET is the same as the stopping power. (the internet as confused me greatly)
thanks
LET=-\frac{4\pi e^4Nz^2Z}{m_0v^2} (ln\frac{2m_0v^2}{I}-ln(1-\beta^2)-\beta^2)=-\frac{dE}{dx},
where e is the charge of an electron, Z is the atomic number of the material being irradiated, m_0 is the mass, z is the charge number of the beam particle, v is the velocity of the beam particle, I is the average ionisation potential (\approx11.5Z(eV)), \beta=\frac{v}{c} and \frac{dE}{dx} is the energy loss per unit length.
and hence LET is the same as the stopping power. (the internet as confused me greatly)
thanks