Equation for S from state func and C

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SUMMARY

The discussion focuses on deriving an equation for entropy (S) from the heat capacity function C=T^4 and the state function V(T,P) = Aexp(aT-bP). The user initially attempts to derive S using the first law of thermodynamics and finds that dU = TdS leads to dS = T^3 dT. However, they acknowledge the need to incorporate Maxwell relations for a complete solution. Ultimately, the correct approach involves using the relation \(\frac{\partial S}{\partial V}_T = \frac{\partial P}{\partial T}_V\) to define S with an integration factor of T.

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  • Understanding of thermodynamic principles, specifically the first law of thermodynamics.
  • Familiarity with Maxwell relations in thermodynamics.
  • Knowledge of state functions and their derivations.
  • Basic calculus for integration and differentiation in thermodynamic equations.
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  • Study the derivation of entropy from thermodynamic potentials.
  • Learn about Maxwell relations and their applications in thermodynamics.
  • Explore the implications of heat capacity functions in phase transitions.
  • Investigate the role of integration factors in thermodynamic equations.
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This discussion is beneficial for students and professionals in thermodynamics, particularly those studying heat capacity, state functions, and entropy calculations. It is especially relevant for physicists and engineers working with liquid systems.

gulsen
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Heat capacity of a liquid is C=T^4 and the state function is V(T,P) = Aexp(aT-bP)
Derive an equation for entropy. Use the relevant Maxwell relations.



dU = T dS - PdV
\frac{\partial U}{\partial T}_V = C = T^4 \Rightarrow U = \frac{T^5}{5} + f(V)
Since it's a liquid, and there're no separate C_V and C_P, I assumed that expansion can be ignored, so dU \approx TdS and
dS = \frac{dU}{T} = T^3 dT

but it's unlikely to be true since I haven't used the state function or Maxwell relation at all. My assumption is probably wrong. Anyone solve the problem?
 
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Solved it.That equation I wrote will have an integration factor f(V).
Using \frac{\partial S}{\partial V}_T = \frac{\partial P}{\partial T}_V, we have the solution for S, this time with an integration factor of T. By compraison of these two statements of S, it's perfectly defined.
 

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