Equation for S from state func and C

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Heat capacity of a liquid is C=T^4 and the state function is V(T,P) = Aexp(aT-bP)
Derive an equation for entropy. Use the relevant Maxwell relations.



dU = T dS - PdV
\frac{\partial U}{\partial T}_V = C = T^4 \Rightarrow U = \frac{T^5}{5} + f(V)
Since it's a liquid, and there're no separate C_V and C_P, I assumed that expansion can be ignored, so dU \approx TdS and
dS = \frac{dU}{T} = T^3 dT

but it's unlikely to be true since I haven't used the state function or Maxwell relation at all. My assumption is probably wrong. Anyone solve the problem?
 
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Solved it.That equation I wrote will have an integration factor f(V).
Using \frac{\partial S}{\partial V}_T = \frac{\partial P}{\partial T}_V, we have the solution for S, this time with an integration factor of T. By compraison of these two statements of S, it's perfectly defined.
 
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