Equation for spring force for a cylinder on compressed air

AI Thread Summary
The discussion focuses on modeling the suspension of a mountain bike using a Rock Shox Monarch RT3 shock, which utilizes compressed air as a spring mechanism. The shock features an adjustable air pressure, a negative spring to reduce breakaway force, and adjustable compression and rebound dampers. The user employs the formula F=P*A to calculate force on the piston and applies Boyle's law along with the adiabatic gas constant to model compression. They seek to create a Force/Displacement graph and request assistance in improving their gas compression model and understanding damping forces. The importance of considering the nature of compression—slow versus sudden—is also highlighted.
CK328
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Evening all,
I've recently undertaken a project where my roll is to analyse the suspension of a mountain bike. The suspension unit in question is a Rock Shox Monarch RT3. To give a brief summary:

The shock uses compressed air as the spring, the pressure is adjustable via an air valve.
The shock also has a negative spring- a separate air chamber which opposes the main spring and reduces the breakaway force to get the shock moving.
The shock features adjustable compression and rebound dampers.

The first thing is to try and model the air spring. Currently, to find the force on the piston, I'm using F=P*A.
Then I'm using Boyle's law P1*V1=P2*V2 to model the compression.
Since the compression is not isothermal, I've added the adiabatic gas constant gamma.
P1*V1^gamma=P2*V2^gamma.

I want to get a decent Force/Displacement graph for the air spring so my final formula is:
F=P0*A*(V0/(V0-chang in V)^1.4
where P0 is the initial pressure and V0 is the initial volume.

If anyone can offer a more accurate way to model the compression of a gas please let me know!

I also don't really know where to start with modelling the damping forces other than F=cv so anyhelp would be greatly appreciated.

Cheers.
 
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You just want to make sure that the adiabatic compression is applicable for the situation in hand.
Compressing the shock slowly - say by applying a load - will probably get you a different result to compressing suddenly like if the wheel hits a rock.
 
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