Equation help

1. Sep 6, 2005

thschica

A ball is droped from a stadium.It hits the ground 2.29 seconds later.How high is the stadium?Do I use this equation?.5at^2(Thant is wrong isnt it?) How fast is the ball going when it hits the ground?(what equation do I use on this one?)

Last edited: Sep 6, 2005
2. Sep 6, 2005

TD

I'm assuming no initial speed, then the height h is given by:

$$h = h_0 - \frac{{gt^2 }}{2}$$

Here, $h_0$ is the initial height, so what you are looking for. You choose h = 0, because that's where it hits the ground. Then fill in t and g and solve for $h_0$.

3. Sep 6, 2005

thschica

In this case would the answer be about 25.7 meters? And How do I tell How fast the marble is going?

4. Sep 6, 2005

TD

That seems to be correct yes.

For the other question, use a relation between acceleration, speed and time. If time is in s and acceleration in m/s², what would give speed (m/s)?

5. Sep 6, 2005

thschica

would that equation be the y='s one?

6. Sep 6, 2005

TD

I was thinking about v = at

7. Sep 6, 2005

thschica

I have another question.If something is dropped and hits the ground one second later how high is it? With that equation I got 7.1.Why is it not 9.8 meters?

8. Sep 6, 2005

TD

Because it's not the speed which is 9.8m/s but the acceleration which is 9.8m/s².
Are you sure you got 7.1 though?

9. Sep 6, 2005

thschica

No I got 4.9 sorry

10. Sep 6, 2005

thschica

Would the ball be going 22m/s before it hit the ground?

11. Sep 6, 2005

TD

That is correct.

You see, an acceleration of 9.8m/s² means that after a full second, the speed has increased 9.8m/s. So when dropping something with no initial speed, it only reaches the speed of 9.8m/s after the full second, so when it hits the ground in your example.

The avarage speed was 9.8/2 = 4.9, exactly what you found

That seems correct, approximately.

12. Sep 6, 2005

thschica

Thank You so much TD

13. Sep 6, 2005

TD

No problem

14. Sep 6, 2005

thschica

Say someone threw the ball up and it didnt hit the ground until 3.53 seconds later how do I find out the ending velocity?What if it was thrown down and hit the ground 1.81 seconds later?

15. Sep 6, 2005

TD

Thrown up would require the initial height and thrown down the initial speed, unless there is none.

Perhaps someone else can help, I'm logging off. 2.50 AM here, good luck!