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Equation help

  • Thread starter thschica
  • Start date
47
0
A ball is droped from a stadium.It hits the ground 2.29 seconds later.How high is the stadium?Do I use this equation?.5at^2(Thant is wrong isnt it?) How fast is the ball going when it hits the ground?(what equation do I use on this one?)
 
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Answers and Replies

TD
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I'm assuming no initial speed, then the height h is given by:

[tex]h = h_0 - \frac{{gt^2 }}{2}[/tex]

Here, [itex]h_0[/itex] is the initial height, so what you are looking for. You choose h = 0, because that's where it hits the ground. Then fill in t and g and solve for [itex]h_0[/itex].
 
47
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In this case would the answer be about 25.7 meters? And How do I tell How fast the marble is going?
 
TD
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That seems to be correct yes.

For the other question, use a relation between acceleration, speed and time. If time is in s and acceleration in m/s², what would give speed (m/s)?
 
47
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would that equation be the y='s one?
 
TD
Homework Helper
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I was thinking about v = at
 
47
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I have another question.If something is dropped and hits the ground one second later how high is it? With that equation I got 7.1.Why is it not 9.8 meters?
 
TD
Homework Helper
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Because it's not the speed which is 9.8m/s but the acceleration which is 9.8m/s².
Are you sure you got 7.1 though?
 
47
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No I got 4.9 sorry
 
47
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Would the ball be going 22m/s before it hit the ground?
 
TD
Homework Helper
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thschica said:
No I got 4.9 sorry
That is correct.

You see, an acceleration of 9.8m/s² means that after a full second, the speed has increased 9.8m/s. So when dropping something with no initial speed, it only reaches the speed of 9.8m/s after the full second, so when it hits the ground in your example.

The avarage speed was 9.8/2 = 4.9, exactly what you found :smile:

thschica said:
Would the ball be going 22m/s before it hit the ground?
That seems correct, approximately.
 
47
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Thank You so much TD
 
TD
Homework Helper
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No problem :smile:
 
47
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Say someone threw the ball up and it didnt hit the ground until 3.53 seconds later how do I find out the ending velocity?What if it was thrown down and hit the ground 1.81 seconds later?
 
TD
Homework Helper
1,020
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Thrown up would require the initial height and thrown down the initial speed, unless there is none.

Perhaps someone else can help, I'm logging off. 2.50 AM here, good luck!
 

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