shonen
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Equation of a Surface relative to the standard basis is
X1^1 + 2X2^2 + 3x^3 -4x1x2 -4x2x3 =0
Now the question ask to find the equation of above surface relative to the cordinate system with basis vectors
F1= (2/3,2/3,1/3)
F2= (1/3,-2/3,2/3)
F3= (2/3,-1/3,-2/3)
Now i found the transition matrix from the standard basis ( (1,0,0),(0,0,1),(0,0,1) ) to (F1,F2,F3) which was found to be
(2/3, 2/3, 1/3)
(1/3,-2/3, 2/3)
(2/3 -1/3,-2/3)
and got an arbitrary vector (a,b,c) in coordinate system in terms of coordinate (x1,x2,x3) relative to the standard basis
27a = 2x1 + 2x2 +x3
27b = x1 -2x2 +2x3
27bc= 2x1 -x2 -2x3
Problem is expressing the above equation of a surface in terms of a,b,and c.
X1^1 + 2X2^2 + 3x^3 -4x1x2 -4x2x3 =0
Now the question ask to find the equation of above surface relative to the cordinate system with basis vectors
F1= (2/3,2/3,1/3)
F2= (1/3,-2/3,2/3)
F3= (2/3,-1/3,-2/3)
Now i found the transition matrix from the standard basis ( (1,0,0),(0,0,1),(0,0,1) ) to (F1,F2,F3) which was found to be
(2/3, 2/3, 1/3)
(1/3,-2/3, 2/3)
(2/3 -1/3,-2/3)
and got an arbitrary vector (a,b,c) in coordinate system in terms of coordinate (x1,x2,x3) relative to the standard basis
27a = 2x1 + 2x2 +x3
27b = x1 -2x2 +2x3
27bc= 2x1 -x2 -2x3
Problem is expressing the above equation of a surface in terms of a,b,and c.
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