Equation of Motion for 2 DOF spring damper system

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SUMMARY

The discussion focuses on deriving the differential equations of motion for a two-degree-of-freedom (2 DOF) spring-damper system. The equations provided are mx'' + c1x' + k1x = 0 and my'' + c2y' + k2y = 0, which represent the motion in the absence of external forces. Additionally, the impact of a uniform angular velocity on the system is explored, with transformations for the mass center position given by Xnew and Ynew. Gravity is not considered in this analysis, as the system operates in a rotating frame.

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  • Understanding of differential equations in mechanical systems
  • Familiarity with spring-damper system dynamics
  • Knowledge of rotational motion and angular velocity concepts
  • Ability to perform coordinate transformations in physics
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  • Study the derivation of equations of motion for multi-degree-of-freedom systems
  • Learn about the effects of Coriolis forces in rotating frames
  • Explore the application of Lagrangian mechanics to dynamic systems
  • Investigate the stability analysis of spring-damper systems under rotation
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Mechanical engineers, physicists, and students studying dynamics and control systems will benefit from this discussion, particularly those interested in the behavior of spring-damper systems in rotating frames.

ufone317
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Please guide me towards the "differential equation of motion" for the following 2 DOF Spring-damper system.

Image.jpg


And furthermore, if above system is in a uniform speed rotating frame, then what can be the effect on this system?


Thank you very much.
 
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Please write the equation for one dof.

Does gravity g apply to y-direction?


What force must be considered in a rotating body?
 
Thank you for your reply.

m*(d2x/dt2)+c*(dx/dt)+k*x = 0 is the equation for one axis.

No effect of gravity is considered here.

The whole frame is rotating at an uniform angular velocity.

If you can provide equation for static (i-e. not rotating) case, that's also fine.
 
Correct me if I'm wrong.

Here are the motion equations;

mx'' + c1x' + k1x' = 0 (Not forced)
my'' + c2y' + k2y' = 0 (Not forced)

Suppose the frame is rotated thru angle q,

In this case, the mass center position with respect to the frame F is

Xnew = x*cos(q) - y*sin(q)
Ynew = y*cos(q) + x*sin(q)

You can simply differentiate Xnew and Ynew. Once and twice, then replace in motion equations

Xnew' = cos(q)*(x'-yq*') - sin(q)*(y'+xq*')
Xnew'' = x''*cos(q) - 2*x'*q'*sin(q) - x*q''*sin(q) - x*q'*q'*cos(q)
-y''*sin(q) - 2*y'*q'*cos(q) - y*q''*cos(q) + y*q'*q'*sin(q)

Note that q''=0. Eliminate some of the terms above and do the same thing for y-axis
 

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