- #1
phyico
- 5
- 0
Determine the equation 1 the tangent to the given function, at the given point.
y = (3x^-2 - 2x^3) , @ (1,1)
y = (3x^-2 - 2x^3) , @ (1,1)
The equation of the tangent line for y = -7x + 5 at the point (1,1) is y = -7x + 5.
The slope of the tangent line for y = -7x + 5 at the point (1,1) is the same as the slope of the original line, which is -7.
The point (1,1) is the point of tangency, where the tangent line touches the original line y = -7x + 5. It is also the point where the slope of the tangent line is equal to the slope of the original line.
Yes, you can use the equation of the tangent line to find other points along the line by plugging in different values for x. However, these points will not necessarily be points of tangency and the slope of the line may not be the same as the slope of the original line.
The equation of the tangent line for y = -7x + 5 at the point (1,1) is a representation of the slope and point of tangency of the original line. It is a linear equation that shares the same slope as the original line, but passes through the point of tangency (1,1) instead of the y-intercept (0,5).