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Equation of Tangent

  1. Mar 5, 2009 #1
    Determine the equation 1 the tangent to the given function, at the given point.

    y = (3x^-2 - 2x^3) , @ (1,1)
     
  2. jcsd
  3. Mar 5, 2009 #2
    pretty sure you need to take the derivative of that. The dy/dx (derivative) you get out of that after plugging everything in is your slope of the tangent. Then just solve for your y-intercept.

    *edit* The other questions you just posted are really the same idea as this.
     
    Last edited: Mar 5, 2009
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