Equation of Tangent

Determine the equation 1 the tangent to the given function, at the given point.

y = (3x^-2 - 2x^3) , @ (1,1)
pretty sure you need to take the derivative of that. The dy/dx (derivative) you get out of that after plugging everything in is your slope of the tangent. Then just solve for your y-intercept.

*edit* The other questions you just posted are really the same idea as this.
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