Equation of the tangent line at (0, pi/2)

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Find the equation for the line that is tangent to the given formula if y = pi/2 when x = 0

Homework Equations



(x+1)dy - [(1/2)secycscy]dx = 0

The Attempt at a Solution



I tried to do this, and I got that

dy/dx = 1 / (0*0), which is infinity.

So...

y = \infty?
 
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OK, so the slope is undefined. What kind of line has a slope that's undefined?
 
So it's a vertical line and no longer a function. That's the answer?
 
Your original problem was to find the tangent line. Nothing was said about being a function. What is the equation of the vertical line through (0, pi/2)?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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