Equations of state -- Partial derivatives & Expansivity

AI Thread Summary
The discussion revolves around deriving the coefficient of volume expansion (β) expressed as β = -1/ρ (∂ρ/∂T) at constant pressure. Participants clarify the relationship between density (ρ) and volume (v), noting that ρ = 1/v. The conversation emphasizes using the chain rule for derivatives to transition between volume and density. A participant initially struggles with the substitution but eventually finds the solution with guidance. The thread concludes with a successful resolution of the problem.
Mia_S
Messages
7
Reaction score
0

Homework Statement



Show that the coefficient of volume expansion can be expressed as

β= -1÷ρ (∂ρ÷∂T) keeping P (pressure) constant
Where rho is the density
T is Temperature

Homework Equations


1/v =ρ
β= 1/v (∂v÷∂T) keeping P (pressure ) constant

The Attempt at a Solution


I started with the original equation (β= 1/v (∂v÷∂T) ) ,substituted ρ for 1/v and got stuck . What should I do next? What's the solution?

Thank you!
 
Physics news on Phys.org
Mia_S said:
substituted ρ for 1/v and got stuck
"Stuck" where?
 
Bystander said:
"Stuck" where?
Here, β= ρ(∂v÷∂T)
 
You're using "ρ = 1/v," so what's the next step?
 
  • Like
Likes Mia_S
Bystander said:
You're using "ρ = 1/v," so what's the next step?
I don't know :( ...Should I change the partial derivative to 1/(∂T÷∂v) ?
 
May I suggest you use the chain rule of derivatives since V=1/rho=(rho)^-1. Take the derivative of the outside function times the derivative of the inside.
 
  • Like
Likes Mia_S
If v = 1/ρ, then, in terms of ρ and dρ, dv = ??

Chet
 
  • Like
Likes Mia_S
I got it! Thank you :)
 
Back
Top