Equilibrium of Three Positively Charged Beads

AI Thread Summary
The discussion centers on finding the equilibrium position of a third bead between two positively charged beads on an insulating rod. It emphasizes that the specific charge of the third bead is irrelevant for determining its equilibrium position, as the focus is on the balance of forces. Participants suggest working symbolically with variables instead of numerical values to derive the equilibrium location. The equilibrium point is where the net force on the third bead is zero, which can be calculated in terms of the distance d. The conversation highlights the importance of understanding the principles of Coulomb's Law in solving such problems.
define_normal
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Homework Statement


Two small beads having positive charges 3q and q are fixed at the opposite ends of a horizontal, insulating rod, extending from the origin to the point x = d. A third small bead (in the middle) is free to slide on the rod. At what position is the third bead in equilibrium? Can it be stable in equilibrium?


Homework Equations


Coulomb's Law
F = ke (q1q2)/r^2


The Attempt at a Solution


I'm not sure how to go about this problem because I don't know the charge of the third bead.
 
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define_normal said:
... I don't know the charge of the third bead.
You don't know any of the values, do you? Work symbollically. That is, just use q's and r's and such, instead of "actual numbers".
 
turin said:
You don't know any of the values, do you? Work symbollically. That is, just use q's and r's and such, instead of "actual numbers".

Hmm. So in order for me to do that, I don't need to know the charge of the third particle?
 
define_normal said:
Hmm. So in order for me to do that, I don't need to know the charge of the third particle?
That's right. You would need to know the charge if you wanted to calculate a non-vanishing force. But, the problem stipulates equilibrium, so it doesn't matter. You are looking for the location where - something, regardless of the amount of charge that is placed there - will calculate to be zero. Even then, you have to calculate this location symbolically (i.e. in terms of d).
 
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