1. Two small beads having a positive charges 3q and q are fixed at the opposite ends of a horizontal, insulating rod, extending from the origin to point X. This length is the distance (d). A third small charged bead (Q) is free to slide on the rod. At what position is the third bead in equilibrium? 2. Coulomb's Law is used for this problem. F = kqq/d F[/SUB] = kQ(3q)/x[/SUP] F[/SUB] = kQq/(d-x)[/SUP] F[/SUB] = F[/SUB] 3. I am attempting to solve for x. 3 (d-x)[/SUP] = (x)[/SUP] I know I could make both side a square root so I have x one side, but I need help beyond this. I also need to show all steps. Thanks!