Equilibrium Problem - Forces acting on beam supports

AI Thread Summary
A 160-kg horizontal beam is supported at both ends, with a 300-kg piano positioned a quarter of the way from one end. To find the vertical forces on each support, the summation of vertical forces must equal zero, leading to the equation ΣFy = 0 = Fy - Fg - Fp. The next step involves calculating moments about point A to determine the force on support B, followed by moments about point B to find the force on support A. Drawing a diagram to visualize the forces and distances is essential for accurate calculations. Understanding these principles is crucial for solving equilibrium problems involving beams and supports.
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1. A 160-kg horizontal beam is supported at each end. A 300-kg piano rests a quarter of the way from one end. What is the vertical force on each of the supports?



2. Summation of Forces in the y = 0.



3. Going off the above equation, I *think* it would be that ΣFy=0=Fy-Fg-Fp, which would become Fg+Fp=Fy. However, I am not sure if this logic is correct, and I'm unsure where to go from there.

Any help is greatly appreciated!
 
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this question involves moments about a point. so firsty you want to draw a diagram of where all the forces are. so you have two supports (call them A and B) and the mass of beam will be halfway between them (0.5L) and the mass of the piano will be a quater the distance from support A( 0.25L).

now you want to take moments about point A, to find the force acting on support B, and then moments about point B, to find the force acting on support A.
 
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