1. The problem statement, all variables and given/known data 5.0 kg of ice at 0◦ is put into 3.0 kg of water at 20◦C. Assuming that they are isolated, that cH2O = 4186 J /kg K , and that L = 3.3 × 105 J/ kg how much ice is left when the system comes to equilibrium? 2. Relevant equations Q= +/- mL Q=mcΔT 3. The attempt at a solution mLice+mcΔTwater=0 5(3.3×105)+3(T-293)(4186)=0 T=266.7K This answer is clearly incorrect as it would give you a negative Celsius temperature. Also how would you find mass from this? Any help would be much appreciated!