Equivalence of d and p Metrics on X

  • Thread starter Thread starter hypermonkey2
  • Start date Start date
  • Tags Tags
    Equivalent
hypermonkey2
Messages
101
Reaction score
0

Homework Statement


Show that d and p are equivalent metrics on X where p=d(x,y)/(1+d(x,y))



Homework Equations


ive proved already that p is indeed a metric too (if d is a metric).


The Attempt at a Solution



I believe I am supposed to use the Lipschitz condition where there exits constants A and B st for all x,y,

Ap<=d<=Bp

but i think i can actually prove that one of these two constants cannot exist... and i using the wrong definitions? Thanks!
 
Physics news on Phys.org
Two metrics are equivalent if they induce the same topology. Isn't that the real definition? It is true that Ap<=d<=Bp shows that. But isn't it also true that for a metric topology what really determines the topology is the 'small' sets? If you can show there is a condition like that for say d<=1. That would also suffice, it doesn't have to hold for ALL x,y. Just for nearby ones.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top