Equivalence of two sine arguments

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The discussion revolves around the equivalence of the sine functions Asin(kx-wt+pi) and Asin(wt-kx) as mentioned in Hecht's optics. Participants explore the fundamental reason behind this equivalence, suggesting that it stems from trigonometric identities. One contributor highlights the usefulness of the identity sin(a+b)=sin(a)cos(b)+sin(b)cos(a) in understanding the relationship. Another participant shares a geometrical argument using the trigonometric circle to arrive at the same conclusion. The conversation emphasizes the application of trigonometry to solve the problem effectively.
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Homework Statement



Hecht in his optics mentions that Asin(kx-wt+pi) is equivalent to Asin(wt-kx)
w=greek omega

Homework Equations


What is the fundamental reason behind this?

The Attempt at a Solution



I have a hunch it's plain trigonometry applied, but none of the things that I can think of bring up this result.
 
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Do you know the identity sin(a+b)=sin(a)cos(b)+sin(b)cos(a)?
 
yes, i do it works that way and thank you very much. I solved it too with a geometrical argument on the trig circle, but i like your approach much better.
 
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