Equivalence Principle: Paper on Internal Observer Effects

ith
Messages
12
Reaction score
0
Hi! How this paper relates to the equivalence principle?

http://arxiv.org/pdf/gr-qc/0701084.pdf

"in contrast to the situation with static gravitational forces, the effects of accelerative gee-forces on the internal observer are increased"
 
Physics news on Phys.org
The affects on the internal observer are the same regardless of whether the stasis chamber is being accelerated or subjected to an external gravitational field.

Assuming the article is accurate (and on cursory review, it is), in both cases the internal observer would experience a magnified G-force.
 
The paper says, that on Earth's surface "gravitational field on an inside observer is effectively dampened". Thus my question.
 
I didn't read through section 3 before.
There must be something wrong with Janca's math in that section.
I would say section 3.1 is more accurate than 3.2. Obviously, they should both be the same.
 
  • Like
Likes 1 person
I asked a question here, probably over 15 years ago on entanglement and I appreciated the thoughtful answers I received back then. The intervening years haven't made me any more knowledgeable in physics, so forgive my naïveté ! If a have a piece of paper in an area of high gravity, lets say near a black hole, and I draw a triangle on this paper and 'measure' the angles of the triangle, will they add to 180 degrees? How about if I'm looking at this paper outside of the (reasonable)...
From $$0 = \delta(g^{\alpha\mu}g_{\mu\nu}) = g^{\alpha\mu} \delta g_{\mu\nu} + g_{\mu\nu} \delta g^{\alpha\mu}$$ we have $$g^{\alpha\mu} \delta g_{\mu\nu} = -g_{\mu\nu} \delta g^{\alpha\mu} \,\, . $$ Multiply both sides by ##g_{\alpha\beta}## to get $$\delta g_{\beta\nu} = -g_{\alpha\beta} g_{\mu\nu} \delta g^{\alpha\mu} \qquad(*)$$ (This is Dirac's eq. (26.9) in "GTR".) On the other hand, the variation ##\delta g^{\alpha\mu} = \bar{g}^{\alpha\mu} - g^{\alpha\mu}## should be a tensor...
Back
Top