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Equivalence Relation

  1. Mar 3, 2010 #1
    1. The problem statement, all variables and given/known data

    Consider the set A={(u,v,w) in R^3 : u^2+v^2>0} and define a relation ~ on A by (u,v,w)~(u',v',w') IFF there exists a "k" in R, where k doesnt equal 0: (u',v',w')=(ku,kv,kw)

    Prove that ~ is an equivalence relation of A


    2. Relevant equations
    I honestly dont know where to start, i know i need to satisfy the reflexive, symmetric & transitive requirements but i dont even know what the relation is here. Any help is very much appreciated.


    3. The attempt at a solution
     
  2. jcsd
  3. Mar 3, 2010 #2

    vela

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    You're given the relation. Two vectors (u,v,w) and (u',v',w') are related if they are non-zero multiples of each other. For example, (1,1,1) ~ (2,2,2) since (2,2,2)=(2x1, 2x1, 2x1), i.e. k=2.
     
  4. Mar 3, 2010 #3
    Ok, So to show its reflexive i can pick an real numbers? I can say (u,v,w)=(1,1,1) so (1,1,1) R (1,1,1) ???
     
  5. Mar 3, 2010 #4
    No, for reflexive, you'd need to look at a general triple (u,v,w). What does it mean to have
    (u,v,w) ~ (u,v,w) ?

    Write it out and find a value for k.

    You'll need to work with general triples for all of the axioms for an equivalence relation.
    (if you really get stuck, you might work with specific points to get a handle on what's happening, but you can't choose specific points for the proof)
     
  6. Mar 3, 2010 #5

    vela

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    No, I was just using specific numbers as an example. As Mathnerdmo said, for a proof, you need to show it's true for the general case.
     
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