Equivalent Capacitance or Resistance and Kirchoff's rules

AI Thread Summary
The discussion focuses on determining the new equivalent RC circuit when capacitors are filled with a dielectric material. The key equations involved include the capacitance with a dielectric, C = KC, and the relationships between voltage, current, and charge. Participants clarify that the problem likely requires finding total resistance and capacitance for a simplified circuit with one resistor and one capacitor. It is confirmed that capacitors in series reduce total capacitance, while those in parallel add directly. The final expression for total capacitance is proposed as Ctot = 4KC, based on the given values.
lookingforhlp
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Homework Statement


If each capacitor is filled with a dielectric material (with constant K, kappa), what is the new equivalent RC circuit? All resistors have equal value, and capacitors have equal value (without a dielectric), C.

Homework Equations


C = (Epsilon * Area) / Distance
C with a dielectric is = KC

V=IR

Q=CV

all the resistor and capacitance equivalent equations


The Attempt at a Solution


(Please see attached image for the RC Circuit)

I guess that it's asking for the current? Not sure what "new equivalent RC circuit" means.

I need to know what this is asking before I try it...anyone have any ideas?
 

Attachments

  • RC Circuit.png
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I presume that they want you to find the component values for an equivalent circuit having just one resistor and one capacitor.
 
So just the total resistance and total capacitance?
 
In that case Rtot = 2R and Ctot = 4K*epsilon*area/distance
 
You're given the original capacitor values, C. You're not given area or distance. So express the resulting capacitance in terms of C.
 
Ctot = 4KC?
 
Sure.
 
lookingforhlp said:
Ctot = 4KC?

Capacitors in series add up, but in parallel they actually reduce the total capacitance. The equation should be easily found in your book.

Someone please correct if I am wrong.
 
I was pretty sure it was the other way around...let me double check
 
  • #10
Capacitors in parallel add directly.
 
  • #11
I agree
 
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