Equivalent circuits resistor problem

AI Thread Summary
The discussion focuses on solving a resistor equivalent circuit problem, specifically finding the equivalent resistance (Req). Participants suggest breaking the circuit into two parallel sets, with one user confirming the calculation for Parallel2 as correct. They explore the connections between resistors R1, R4, and R2, questioning how they relate to the circuit's negative terminal. A visual aid is recommended to clarify the circuit layout. The final proposed solution for Req involves combining the resistances in a specific formula.
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Homework Statement



Find Req.


Homework Equations



Series: R1 + R2 + ...

Parallel: 1/(1/R1 + 1/R2 + ...)

The Attempt at a Solution



There's no solution for this one in the book but I'm thinking that I can break this up into two parallel sets. Parallel1 = (R1*R4)/(R1 + R4) and Parallel2 = (R3*R2)/(R3 + R2). Is that correct?
 

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It's not exactly very easy figuring out that diagram, why not do it properly on paint and then upload the image?
 
NewtonianAlch said:
It's not exactly very easy figuring out that diagram, why not do it properly on paint and then upload the image?

Yeah it didn't keep the white space. Sorry
 
Your parallel2 is correct.

What is inbetween the right end of R4 and the bottom end of R1?
 
Integral said:
Your parallel2 is correct.

What is inbetween the right end of R4 and the bottom end of R1?

The same voltage?
 
Oh wait.. If I combine Parallel2 into the circuit as one unit it will now be in between the right end of R4 and the bottom end of R1.
 
If you consider R1 and R4 in parallel, it has to be connected to the negative terminal right? What's helping completing the circuit?
 
NewtonianAlch said:
If you consider R1 and R4 in parallel, it has to be connected to the negative terminal right? What's helping completing the circuit?

Parallel2
 
http://slimber.com/index.php?image=resistors.g80803

See if that helps you visualize it better
 
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  • #10
NewtonianAlch said:
http://slimber.com/index.php?image=resistors.g80803

See if that helps you visualize it better

Sort of.. If it was drawn like that then would the solution be:

1/(1/R1 + 1/(R4 +R2) + 1/R3) ?
 
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