Error Analysis of Sin(x) with x=2±0.2

AI Thread Summary
To perform error analysis on the sine function for x=2±0.2, first, calculate the derivative of y=sin(x), which is f'(x)=cos(x). Then, evaluate cos(2) to find its value, and multiply it by the uncertainty Δx (0.2) to determine the standard deviation Δy. The final result will express y in the form mean±error, where the mean is sin(2) and the error is the calculated Δy. This method effectively quantifies the uncertainty in the sine function based on the given range of x.
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Homework Statement



let x=2±0.2
y=sin(x)

write y in the form mean±error

i don't know how to perform error analysis on the sine function help please

Homework Equations





The Attempt at a Solution


i looked through a physics textbook and saw something which might help me

(sigma)^2=d^2f/dx^2*\sigma1^2


 
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The proper formula is that when you have :

x ± Δx,
where Δx is the standard deviation of the measurement x

and y = f(x)

then the standard deviation Δy for given x ± Δx is:

Δy = |f'(x)| Δx

Can you apply that to your problem?
 
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