- #1

kald13

- 9

- 0

[itex]2(-2^3)-3(-2^2)[/itex]

2(-2^3) is correctly calculated as -16 independently, and 3(-2^2) is correctly calculated as 12 (again, independently) for a difference of -28, but my calculator is returning -4.

No matter how I enter the equation, the only way I obtain a correct result is by first defining a variable as -2 and then substituting that variable in for -2 in the equation.

Is this problem repeated on anyone else's unit? And if you've encountered this sort of problem before, is there a way to correct it?