Error Propagation for Tube Volume

AI Thread Summary
To calculate the error in the volume of a cylindrical tube with a length of 16±0.1 cm and a radius of 8±0.1 cm, the volume is first determined using the formula V = π*r²*h. The discussion centers on whether to account for the radius error twice due to its squared term in the volume formula. It is clarified that when variables are the same, their errors should not be treated as independent, which affects the error propagation calculation. The correct approach involves using the error propagation equation while considering the dependency of the radius terms. Understanding this is crucial for accurate uncertainty analysis in measurements.
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Homework Statement


You have a cylindrical tube for which you know the length is 16±0.1 cm and the radius is 8±0.1 cm, what is the error of the volume?

Homework Equations


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The Attempt at a Solution


V = π*82*16 = 3216.99 cm

But since the r term is squared, must we account for its error twice in the error propagation equation?

σV = 3216.99*√((0.1/16)2+(0.1/8)2+(0.1/8)2

Or does this require only one (0.1/8)2 term?
 
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