Why Multiply Carbon Isotope Mass Numbers by 1.67x10^-27 kg?

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The discussion centers on the need to multiply carbon isotope mass numbers (12, 13, 14) by 1.67x10^-27 kg to estimate their atomic masses for a mass spectrometry problem. It is clarified that while atomic mass units (amu) are commonly used, the conversion to kilograms is necessary for calculations involving electric and magnetic fields. The user confirms that since the equation requires mass in kilograms, they should use the conversion factor provided. The importance of understanding the relationship between mass, charge, and the resulting motion of ions in a mass spectrometer is emphasized. Ultimately, the conversion to kilograms is essential for accurate calculations in this context.
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Here's a verbatim section of the problem:
" The source contains carbon isotopes of mass numbers 12, 13, 14 from a long-dead piece of a tree. (To estimate atomic masses, multiply by 1.67x10^-27kg). "

My question is isn't the 12, 13, & 14 in the atomic mass units already (Carbon-12 has an amu of 12)? Why would I need to multiply? And if I do need to multiply, should I leave it in kg or convert to g?

Thank you.
 
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I'm afraid you haven't given enough of the problem statement for us to know what exactly you are going to be doing with the carbon masses so that we can know if you really need to convert to some unit such as kg. Since whoever wrote the question took the effort to provide a conversion factor for you, it is pretty likely that you really do need to make use of the conversion factor.

To an approximation, an atomic mass unit is kinda sort of the mass of a neutron or the mass of a proton. This glosses over the fact that the proton's mass is a little different than the neutron's mass. Also, there are issues of binding energy when protons and neutrons bind together to form a nucleus.

Way back when I was a kid, I am pretty sure they liked to call either the mass of a certain isotope of oxygen a perfect 16.00000 amu, or else maybe it was that the mass of the carbon-12 isotope was taken to be a perfect 12.00000 amu, I can't remember which.
 
I was afraid that would not be enough info, the entire question is as follows:

Suppose the e field between the e plates in the mass spec is 2.48x10^4 v/m and the magnetic fields B=B'=0.68T. The source contains carbon isotopes of mass #s 12, 13, 14 from a dead tree. (estimate masses by x by 1.67x10^-27) How far apart are the lines formed by the singly charged ions of each type on the photographic film?

I thought I would need to multiply since they bothered mentioning it. However, I do not know if I should convert to grams or leave it in kg. The eq I used is r=(mE)/(qBB')

Thanks
 
Nevermind, Telsa is in kg so for it to cancel I have to use kg.

Thanks.
 
Ah yes.

One Tesla is one kilogram[/color] per second squared per ampere.
 
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